(x^2+2x-8)(x-6)=0

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Solution for (x^2+2x-8)(x-6)=0 equation:


Simplifying
(x2 + 2x + -8)(x + -6) = 0

Reorder the terms:
(-8 + 2x + x2)(x + -6) = 0

Reorder the terms:
(-8 + 2x + x2)(-6 + x) = 0

Multiply (-8 + 2x + x2) * (-6 + x)
(-8(-6 + x) + 2x * (-6 + x) + x2(-6 + x)) = 0
((-6 * -8 + x * -8) + 2x * (-6 + x) + x2(-6 + x)) = 0
((48 + -8x) + 2x * (-6 + x) + x2(-6 + x)) = 0
(48 + -8x + (-6 * 2x + x * 2x) + x2(-6 + x)) = 0
(48 + -8x + (-12x + 2x2) + x2(-6 + x)) = 0
(48 + -8x + -12x + 2x2 + (-6 * x2 + x * x2)) = 0
(48 + -8x + -12x + 2x2 + (-6x2 + x3)) = 0

Combine like terms: -8x + -12x = -20x
(48 + -20x + 2x2 + -6x2 + x3) = 0

Combine like terms: 2x2 + -6x2 = -4x2
(48 + -20x + -4x2 + x3) = 0

Solving
48 + -20x + -4x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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